|
An annulus is the region between two
concentric circles.[2]
The
area
of the annulus is the difference between the areas of the circles:
A = π(r12 - r22)
where r1 > r2.
Click here for the answer. Answer: The formula for the area of an annulus is
A = π(r12 - r22),
r1 > r2. Plugging in
3m for r1
and
1m for r2,
we get A = π(32-12)
= π(9-1) = π·8 ≈ 25.13.
| |||||||||
Examples of Annulus
|
1. |
A pipe has an inner radius of 3 cm. It has an outer radius of 3.5 cm.
It is 100 cm long. What is the total volume of the pipe, not including
the empty space inside?
Click here for a hint. Hint: The volume of a cylinder is equal to the area of the base times the height of the cylinder (V = b·h). If the base is an annulus, what is the volume of the pipe? Click here for the answer. Answer: The volume of a pipe is the area of the base of the pipe times the height. The area of the base is A = π(r12 - r22), r1 > r2. So A = π((3.5 cm)2-(3 cm)2) ≈ 3.14159(12.25cm2 - 9cm2) ≈ 3.14159·3.25 cm2 ≈ 10.21 cm2. The volume of the pipe is equal to the area of the base times the height. V ≈ 10.21 cm2 · 100 cm V ≈ 1021 cm3. |
2. |
The same pipe is made of a metal alloy with a density of
3g/cm3.
What is the mass of the pipe in challenge 1?
Click here for the answer. Answer: Using dimensional analysis, cm3·g/cm3 = gm. So multiplying the two quantities will give the correct result. 1021cm3·3gm/cm3 = 3063gm = 3.063kg. |
# | A | B | C | D |
E | F | G | H | I |
J | K | L | M | N |
O | P | Q | R | S |
T | U | V | W | X |
Y | Z |
All Math Words Encyclopedia is a service of
Life is a Story Problem LLC.
Copyright © 2018 Life is a Story Problem LLC. All rights reserved.
This work is licensed under a Creative Commons Attribution-ShareAlike 4.0 International License