Reducing Fractions
Pronunciation: /rɪˈdus.ɪŋɡ ˈfræk.ʃənz/ Explain
To reduce a fraction is to cancel
common factors
in the fraction.
Example 1
Step | Equation | Description |
1 | ![12/15](../../equations/r/reducingfractionseqn01.png) | This is the fraction to reduce. |
2 | ![12/15=(2*2*3)/(3*5)](../../equations/r/reducingfractionseqn02.png) |
Start by finding the prime factorization
of the numerator and the denominator. 12 = 2 · 2
· 3, 15 = 3 · 5. Use the
substitution property of equality to substitute the prime factorization in for
the original value. |
3 | ![(2*2*3)/(3*5)=(2*2)/(5)](../../equations/r/reducingfractionseqn03.png) | Cancel any common factors. |
4 | ![(2*2)/(5)=4/5](../../equations/r/reducingfractionseqn04.png) |
Calculate the numerator and denominator. The fraction is reduced. |
5 | ![12/15=4/5](../../equations/r/reducingfractionseqn05.png) |
We can now conclude that . |
Table 1 |
Example 2
Step | Equation | Description |
1 | ![84/70](../../equations/r/reducingfractionseqn11.png) | This is the fraction to reduce. |
2 | ![84/70=(2*2*3*7)/(2*5*7)](../../equations/r/reducingfractionseqn12.png) |
Start by finding the prime factorization of the numerator and the denominator.
84 = 2 · 2 · 3 · 7,
70 = 2 · 5 · 7. Use the substitution
property of equality to substitute the prime factorization in for the original
value. |
3 | ![(2*2*3*7)/(2*5*7)=(2*3)/(5)](../../equations/r/reducingfractionseqn13.png) | Cancel any common factors. |
4 | ![(2*3)/(5)=6/5](../../equations/r/reducingfractionseqn14.png) |
Calculate the numerator and denominator. The fraction is reduced. |
5 | ![84/70=6/5](../../equations/r/reducingfractionseqn15.png) |
We can now conclude that . |
Table 2 |
Example 3
Step | Equation | Description |
1 | ![(x^2-x-2)/(x^2+4x+3)](../../equations/r/reducingfractionseqn21.png) | This is the fraction to reduce. |
2 | ![(x^2-x-2)/(x^2+4x+3)=((x+1)(x-2))/((x+1)(x+3))](../../equations/r/reducingfractionseqn22.png) |
Start by finding the prime factorization of the numerator and the denominator.
x2 - x - 2 =
( x + 1 )( x - 2 ),
x2 + 4x + 3 =
( x + 1 )( x + 3 ). Use the substitution property
of equality to substitute the prime factorization in for the original value. |
3 | ![((x+1)(x-2))/((x+1)(x+3))=(x-2)/(x+3),x!=1](../../equations/r/reducingfractionseqn23.png) | Cancel any common factors. |
5 | ![x^2-x-2)/(x^2+4x+3)=(x-2)/(x+3),x!=1](../../equations/r/reducingfractionseqn24.png) |
We can now conclude that . |
Table 3 |
References
- McAdams, David E.. All Math Words Dictionary, reduce a fraction. 2nd Classroom edition 20150108-4799968. pg 153. Life is a Story Problem LLC. January 8, 2015. Buy the book
More Information
- McAdams, David E.. Complex Fraction. allmathwords.org. Life is a Story Problem LLC. 3/12/2009. https://www.allmathwords.org/en/c/complexfraction.html.
Cite this article as:
McAdams, David E. Reducing Fractions. 5/3/2019. All Math Words Encyclopedia. Life is a Story Problem LLC. https://www.allmathwords.org/en/r/reducingfractions.html.
Image Credits
Revision History
5/3/2019: Changed equations and expressions to new format. (
McAdams, David E.)
3/29/2019: Added vocabulary links. (
McAdams, David E.)
12/21/2018: Reviewed and corrected IPA pronunication. (
McAdams, David E.)
1/15/2009: Initial version. (
McAdams, David E.)